Line L has equation 2x - 3y = 5. Line M passes through the point (2, -10) and is perpendicular to line L. Determine the equation for line M. A) 2x + 3y = -14 B) 2x - 3y = -26 C) 3x + 2y = -14 D) 3x - 2y = -26
I undestand how to get the slope and everything, but I don't understand how to use the ordered pair it provides...
@Sunshine447 what's the slope of line m?
-3/2?
Good, do you know how to find slope?
using the slope formula and solving?
yes
okay, but how do I involve the ordered pair it gives me?
Let line passes through (x, y) and (x1, y1) and has slope m, then equation is given as \[\frac{y-y1}{x-x1}=m\] here (x1, y1)=(2, -10) and slope is \(\frac{-3}{2}\)
@Sunshine447 I think you can do now, can't you?
i know its c based on the slope, but I don't understand where you get the -14 from
@ash2326 u there?
@Hero can you help me?
Hint: The product of the slopes of two perpendicular lines is - 1
I don't understand... How do you get the -14 from?
*where do you
ok put line l into the standard form.
it is in standard form... isnt it?
sorry i meant y=mx+b then when yo get it into that form you have to plug the points into the equation \[y-y _{1}=m \left( x-x _{1} \right)\]
now the m is the slope from the first line and it has to be the reciprocal. so find that of the equation and plug it in.
y=2/3x+5
thats the mx+b right?
yeah
ok now turn the m into the reciprical
opposite reciprocal or reciprocal?
negative reciprocal
-3/2
ok goo now plug it into the m in to the formula i gave you
is this point slope form?
yes.
ohhhhhh okay I have my formula sheet but I didn't know which one to use. It's c right?
yeah i thinks so.
thanks!
haha a return of favors huh ?
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