Question

What is the equation of the line in standard form that passes through the point (–2, –3) and is parallel to the line y = x + 9?

x – y = 1

x + y = 1

x – y = –5

x + y = –5

Answer 1

k
since it is parallel to the line y=x+9
so ots slope must be equal to the slope of y=x+9
slope of y=x+9 is
m=1
now using point slope form
(-2,-3)
y-y0=m(x-x0)
y-(-3)=1(x-(-2)
simplify it.

Answer 2

1. Let L be the equation of the line we are looking for.
2. Since L is parallel to the line l: y=x+9, then the slope of l is equal to the slope of L,
3. Since the the slope of l=1, then slope of L=1.
4. Using the point slope formula y-y_0=m(x-x_0) we have y-(-3)=1(x-(-2)
=> y+3=x+2 => x-y=1

Answer 3

thank you sooo much!<3