Question

dy/dx = 5y , with y(0) = 3

acan any one here tel me how solve this

Answer 1

dy/dx = 5y


dy/dx = 5y


dy = 5y*dx


dy/y = 5dx


Integrate both sides and tell me what you get

Answer 2

\[\ln y = 5x\]

Answer 3

more like

ln(|y|) = 5x + C

but you pretty much have it

Now solve for y

Answer 4

yeah.thnx
actually thats ware im stucked..
is it \[y=e ^{(5x+C)}\]

Answer 5

ln(|y|) = 5x + C

|y| = e^(5x + C)

|y| = e^(5x)*e^(C)

|y| = e^(C)*e^(5x)

|y| = A*e^(5x)

y = +-A*e^(5x)

where A = e^C

Answer 6

now use the idea that y(0) = 3

Answer 7

to find the value of 'A' (which will help you find C, but that's a bit irrelevant)

Answer 8

thnx... got it solved :D

Answer 9

yw