Question

A player hits a foul ball with an initial vertical velocity of 70 ft/s and an initial height of 5 feet. The maximum height reached by the ball is _____ feet. (Round to the nearest foot and enter only the number.)

Answer 1

was busy somewhere else.
using third equation of motion
\[\Large 2g(h-h_{0})=v_{f}^2-v_{i}^2\]
here g=-32.2 ft/sec^2
vf=0
h0=5ft
so
\[\Large 2*(-32.2)(h-5)=0-(70)^2\]
\[\Large h-5=\frac{70^2}{2*32.2}\]
can you solve for h ??

Answer 2

@AudrianaS

Answer 3

does h=81.09?

Answer 4

yes .you got it.

Answer 5

okay thank you so much!!

Answer 6

you are welcome:)