What is the factored form of each expression? 1. s^4-16 2. d^2-14d+45
No. 1. This is an expression you should begin to recognize. It is the difference of two perfect squares like :\[(a ^{2}-b ^{2})\]which is factored by \[(a+b)(a-b)\]
\[s ^{4}-16=(s ^{2}+4)(s ^{2}-4)=(s ^{2}+4)(s+2)(s-2)\]
A. (s-2)^2(s+2)^2 B. (s-2)(s+2) C. (s-i)(s+i)(s+2) D. (s-2i)(s+2i)(s-2)(s+2)
Thats the answers to 1. hold on and ill type 2
A. (d+9)(d+5) B. (d+9)(d-5) C. (d-9)(d+5) D. (d-9)(d-5)
No. 2. you can factor by find a sum of two numbers equal to -14 and when multiplied is 45.
Back to no. 1, I did not know you were into complex solutions.\[(s ^{2}+4)=(s+2i)(s-2i)\]so substitute that for the (s^2+4)
You can look at No. 2's choices and readily see the pair that add up -14d
Thats why i wrote the answers because some ppl get what im asking wrong
Yes, can you pick out the answer to 1. now?
would not one but two yes the answer to num. 2 is D
No. 2 u got correct. now do No. 1, look at my post where \[s ^{2}+4\]
is the answer to num. 1 D also?
converts or factors to: (s+2i)(s-2i)
Yes, very good.
:) Thank you very much
You're welcome.
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