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Mathematics 15 Online
OpenStudy (anonymous):

What is the factored form of each expression? 1. s^4-16 2. d^2-14d+45

OpenStudy (radar):

No. 1. This is an expression you should begin to recognize. It is the difference of two perfect squares like :\[(a ^{2}-b ^{2})\]which is factored by \[(a+b)(a-b)\]

OpenStudy (radar):

\[s ^{4}-16=(s ^{2}+4)(s ^{2}-4)=(s ^{2}+4)(s+2)(s-2)\]

OpenStudy (anonymous):

A. (s-2)^2(s+2)^2 B. (s-2)(s+2) C. (s-i)(s+i)(s+2) D. (s-2i)(s+2i)(s-2)(s+2)

OpenStudy (anonymous):

Thats the answers to 1. hold on and ill type 2

OpenStudy (anonymous):

A. (d+9)(d+5) B. (d+9)(d-5) C. (d-9)(d+5) D. (d-9)(d-5)

OpenStudy (radar):

No. 2. you can factor by find a sum of two numbers equal to -14 and when multiplied is 45.

OpenStudy (radar):

Back to no. 1, I did not know you were into complex solutions.\[(s ^{2}+4)=(s+2i)(s-2i)\]so substitute that for the (s^2+4)

OpenStudy (radar):

You can look at No. 2's choices and readily see the pair that add up -14d

OpenStudy (anonymous):

Thats why i wrote the answers because some ppl get what im asking wrong

OpenStudy (radar):

Yes, can you pick out the answer to 1. now?

OpenStudy (anonymous):

would not one but two yes the answer to num. 2 is D

OpenStudy (radar):

No. 2 u got correct. now do No. 1, look at my post where \[s ^{2}+4\]

OpenStudy (anonymous):

is the answer to num. 1 D also?

OpenStudy (radar):

converts or factors to: (s+2i)(s-2i)

OpenStudy (radar):

Yes, very good.

OpenStudy (anonymous):

:) Thank you very much

OpenStudy (radar):

You're welcome.

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