Question

PLEEEZZZ HELP! simplify (4x^2+12x-16/2x+10)/(6x+24/x^2+9x+20)

Answer 1

fractorise each expression

\[\frac{4(x +4)(x -1)}{2(x + 5)}\div \frac{6(x + 4)}{(x + 5)(x + 4)}\]

flip the 2nd fraction and multiply

\[\frac{4(x +4)(x -1)}{2(x + 5)} \times \frac{(x + 5)(x + 4)}{6(x + 4)}\]

eliminate common factors... (x +4) and (x +5)will leave

\[\frac{4(x +4)(x - 1)}{2} \times \frac{1}{6}\]

I'll leave you to finish the answer

Answer 2

ooopsss... there is a common factor of 4 that can also be removed

Answer 3

first simplify the top part 4x^2+12x-16/2x+10
factor 4x^2+12x-16= (4x-16)(x-1)
then do the bottom 2x+10= 2(x+5)
then you get (4x-16)(x-1)/2(x+5) for the first part

then simplify the second part 6x+24/x^2+9x+20
Simplify 6x+24= 6(x+4)
factor x^2+9x+20= (x+5)(x+4)
then you get 6(x+4)/(x+5)(x+4) for the second part

then put it all together and simplify:
(4x-16)(x-1) 6(x+4)
------------ /----------
2(x+5) (x+5)(x+4)

cancel out the (x+4) bc there are two of them and one is on the top and one is on the bottom
then flip over the second fraction bc you are dividing
(4x-16)(x-1) (x+5)
------------ /----------
2(x+5) 6

then cancel out the (x+5) bc there are 2 of them and one is on the top and one is on the bottom

then your final answer is (4x-16)(x-1)/12
because you are multiplying all of your top terms together and all of your bottoms terms together
:)

Answer 4

@sgavini @campbell_st neither of your answers are any of my choices! :( theese are my choices!

Answer 5

which is the correct answer ?????? @sgavini @campbell_st

Answer 6

actually mu answer is correct its just that you haven't finished the answer


\[\frac{4(x + 4)(x -1)}{2} \times \frac{1}{6} = \frac{4(x +4)(x -1)}{2 \times 6}\]

are you able to simplify this

Answer 7

if you can tell me how i can!!

Answer 8

lets look at it this way

\[\frac{4(x +4)(x-1)}{12} \]

can you simplify this.... all I've done is complete some multiplication

Answer 9

would it be (x+1)(x-1)/3

Answer 10

here is another option

\[\frac{4(x +4)(x -1)}{4 \times 3}\]

can you see the common factor in the numerator and denominator that can be cancelled

Answer 11

check you answer.... there may be a typo

Answer 12

so is it

Answer 13

correct....

Answer 14

thank you too the moon and back! ;)

Answer 15

good luck

Answer 16

Wow... I didn't think anyone could solve that- it was correct!! Tysm!! O.O