A right circular cylinder has a base whose area is 154 square feet. If the height of the cylinder is 19 feet, what is its lateral area? Use π = 22 over 7
1980 ft2
836 ft2
990 ft2
1672 ft2
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OpenStudy (anonymous):
Figure the radius from the area of the base, first.
OpenStudy (anonymous):
Can you?
OpenStudy (anonymous):
no can you explain how?
OpenStudy (anonymous):
What is the area of a circle, it's the same.. (this is a cylinder).
OpenStudy (anonymous):
ughh this is mkn my head hurt . im sorry ive took 4 exams today so far .
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OpenStudy (anonymous):
Area = π × r2
OpenStudy (anonymous):
So 154 = 22/7 times r^2
What is r?
OpenStudy (anonymous):
to find that wud i half to multiply 22/7 * 154 then divide by 2?
OpenStudy (anonymous):
Not quite.
sqrt(154 times 7/22)
OpenStudy (anonymous):
so it wud be 154 * 22/7 which is 484 then square it ? so it wud be 484^2 ?
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OpenStudy (anonymous):
reread
OpenStudy (anonymous):
im sorry i dont get it . :/
OpenStudy (anonymous):
You multiplied by 22/7 instead of 7/22
OpenStudy (anonymous):
ok i got 49.
OpenStudy (anonymous):
OK, now what?
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OpenStudy (anonymous):
Tell you what, let's go step by step, OK?
OpenStudy (anonymous):
yes please.
OpenStudy (anonymous):
We have
pi r^2 = 154 = (22/7) r^2
OK?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
So multiply both sides by 7
7 x 154 = 22 r^2
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OpenStudy (anonymous):
(7 x 154)/22 = r^2
OK?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Now do the multiplication, then take the square root of both sides
OpenStudy (anonymous):
The 49 is what you got before, but you need the square root.
OpenStudy (anonymous):
so next would be 1,078/22=r^2
then its 49=r^2
then 49^2
n that is 2,401
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OpenStudy (anonymous):
square root
OpenStudy (anonymous):
ooohh sorry . its 7
OpenStudy (anonymous):
Yes! So r = 7. OK?
OpenStudy (anonymous):
yes.
OpenStudy (anonymous):
The other part of the problem is to find the "lateral area", the area of the "skin" on the cyclinder (not counting the ends), like an open tube.
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OpenStudy (anonymous):
There's a formula for that, but I want you to visualize sliding a rubber band down the length of the cylinder. Can you see that?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
The area the rubber band will cover is the perimeter of the circle (length of the rubber band) times how far we roll it
OpenStudy (anonymous):
So the formula is 2 pi r times the height of the cylinder.
OpenStudy (anonymous):
ok . so tht wud be 836
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