Question

solving for q

Answer 1

\[\sqrt{3q}+2=\sqrt{5}\]

Answer 2

Are you trying to check your answer?

Answer 3

\[q=\sqrt{5}-2\sqrt{3}/3 \]

Answer 4

yes

Answer 5

is it \(\large{\sqrt{3q}}\) or \(\large{\sqrt{3}*q}\) ?

Answer 6

@mathslover, she already posted what it was.

Answer 7

i want to confirm ..@helpme9283 so it is : \(\large{\sqrt{3q}}\)

Answer 8

She's not even here anymore.

Answer 9

.@helpme9283 ??

Answer 10

ya it is

Answer 11

ok so ..
\[\large{\sqrt{3q}+2=\sqrt{5}}\]

subtract both sides by 2 ..

Answer 12

what r u getting then?

Answer 13

like .. this :
\[\LARGE{\sqrt{3q}+2-2=\sqrt{5}-2}\]

Answer 14

i got \[\sqrt{5}-2\sqrt{3}/3\]

Answer 15

sorry it is wrong since:
\[\LARGE{\sqrt{3q}=\sqrt{5}-2}\]
\[\large{3q=5+2-4\sqrt{5}}\]
\[\large{3q=7-4\sqrt{5}}\]

Answer 16

hmm.. \[\sqrt{15}-2\sqrt{3}/3 \space?\]

Answer 17

@mathslover, that is not correct.

Answer 18

This guy amazes me. First he rudely interrupts me and then posts his incorrect solution. Then he just logs off.

Answer 19

\((\sqrt{3q})^2 = (\sqrt{5} - 2)^2\)
\(3q = (\sqrt{5} - 2)(\sqrt{5}-2) \\ 3q = (\sqrt{5}(\sqrt{5}-2)-2(\sqrt{5}-2) \\ 3q = 5 - 2\sqrt{5} - 2\sqrt{5} + 4 \\ 3q = -4\sqrt{5} + 9 \\ q = \large\frac{-4\sqrt{5} + 9}{3} \\ q = \large 3 - \frac{ 4\sqrt{5}}{3}\)

Answer 20

sorry .. i just put wrong 2 ^2 as 2 ..
and @Hero you dont need to put extra comments ..
if you are amazed .. then please show it to others .. and dont post such extra compliments about me