Question

Prove that -- \[\dfrac {1} {\sin \left( x-a\right) \sin \left( x-b\right) }=\dfrac {\cot \left( x-a\right) -\cot \left( x-b\right) } {\sin \left( a-b\right) }\]

Answer 1

sum1 replying at last....

Answer 2

i guess it's simply asking for simplification of
cos(x-a)sin(x-b) - cos(x-b)sin(x-a) == sin(a-b)

Answer 3

sin(x-b-(x-a)) = that value ... put back cot back to cosines and sines and ... usual stuff

Answer 4

wait i tried simplifying rhs and it gave 1 is that correct?

Answer 5

no .. you will get LHS

do this on RHS