Prove that -- $$\dfrac {1} {\sin \left( x-a\right) \sin \left( x-b\right) }=\dfrac {\cot \left( x-a\right) -\cot \left( x-b\right) } {\sin \left( a-b\right) }$$

Question

anonymous · Answer

sum1 replying at last....

experimentx · Answer

i guess it's simply asking for simplification of 
cos(x-a)sin(x-b) - cos(x-b)sin(x-a) == sin(a-b)

experimentx · Answer

sin(x-b-(x-a)) = that value ... put back cot back to cosines and sines and ... usual stuff

anonymous · Answer

wait i tried simplifying rhs and it gave 1 is that correct?

experimentx · Answer

no .. you will get LHS
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do this on RHS