y = negative three-halvesx + 4 –3x + 2y = 8
here the probelm in picture form
the first equation is in slope intercept form already i. e.:- y = mx + c where m = slope and c is the y-intercept so if you compare this with your first equation you will have these 2 values
–3x + 2y = 8 equation of a line is y = mx+b where m = slope and b = y-intercept making the given equation agree with the line equation, equate y. we have: -3x+2y=8 2y = 8+3y divide both sides by 2, we have: y = 4 + (3/2)x or y = (3/2)x + 4 for solving y-intercept, substitute 0 to x and solve for y. y = (3/2)(0) + 4 y = 4 so we have point (0,4) as your y-intercept.
im confused
which part?
like i need someone to walk me through everything can u do that with me??
could you be more specific?
like there diffrent part to question okay so for the first one Type the first equation from the group you selected and identify the slope and the y-intercept of the equation. how do we do that
ahh. so you were given –3x + 2y = 8, correct?
so, in order for the given equation agree with the equation of line which is y = mx+b, we equate the given equation –3x + 2y = 8 to y.. so, -3x + 2y = 8 transfer -3x to the other side of the equation, that makes -3x to +3x 2y = 8 + 3x we only need ONE 'y' so we have to dive the whole equation to 2 2y/2 = 8/2 + 3x/2 so we get y = 4 + (3/2)x so from that equation we now have the equation of line, y = mx+b where m = 3/2 and b = 4 arrange it to satisfy the equation of line y = mx+b y = (3/2)x + 4
thats not the first equation though y = -3/2x + 4 is the first one
yes, there must be something wrong. try to recheck the problem.
ah sorry! I did not read the problem. my bad.. so the first equation is y = (-3/2)x + 4 so identify the slope and y-intercept. from the equation of line, y = mx+b, where m is the slope and b is the y-intercept. you can prove the y-intercept by substituting 0 to x. |dw:1343744106596:dw|
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