Solve the following system of equations. Please show your work to receive full credit. x - y = 13 2x + y = 2 Part 2: Explain which method you chose to solve the system and why you felt it was the best choice.
add 2 equations left hand side and right hand side seperately the y terms will get cancelled
Add both equations(elimination).
add the equations together, the y-s will cancel
Is that enough for you to manage it? @rebecca1233
you can solve it in your head this way
And by adding both equations, we mean adding the LHS's and RHS's.
can you help me work it out please
(x - y)+ (2x + y) = (13) + (2) x - y+ 2x + y = 13 + 2 (x + 2x) +( y - y) = (13 + 2)
alright & which method is this cause i was gnna do substitution
x=5
if you wanted to use substitution i would target the y in the second equation
ok what method did u use
Parth says its called (elimination)
ok.. and i got y = -8
which method did you use, correct by the way
yes well done x=5 y=-8
Thanks.. can you guys help with another question i post
x - y = 13 2x + y = 2 [1 -1 | x| 13 ] [2 1 | y | 2 ] [1 -1 | x| 13 ] [0 3 | y | -24 ] R_2 - 2R_1 [1 -1 | x | 13 ] [0 1 | y | -8 ] R_2 / 3 [1 0 | x | 5 ] R_1+R_2 [0 1 | y | -8 ] x=5 y=-8
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