Question

Pleeezzzzz helpp!!! :)solve for x:

Answer 1

the choices are A) x=1/4 and x=2 B) x=-1/4 and X=-2 C)x=1/4 and x=-2 D)x=-1/4 and x=2

Answer 2

Given : solve for x ..
\[\LARGE{\frac{5}{x^2-1}-\frac{2}{x}=\frac{2}{x+1}}\]

Answer 3

now ... first of all .. : add 2/x on both sides

Answer 4

that is :
\[\large{\frac{5}{x^2-1}-\frac{2}{x}+\frac{2}{x}=\frac{2}{x+1}+\frac{2}{x}}\]

\[\large{\frac{5}{x^2-1}=\frac{2}{x+1}+\frac{2}{x}}\]

Answer 5

can you solve this ?

Answer 6

would it end up 7/x^2 ?

Answer 7

I think i should solve this here .. you will get your answer on ur own ?

Answer 8

yes please!

Answer 9

\[\LARGE{\frac{5}{x^2-1}=\frac{2}{x+1}+\frac{2}{x}}\]
\[\LARGE{\frac{5}{x^2-1}=\frac{2x+2(x+1)}{x(x+1)}}\]

Answer 10

what r u getting after simplifying it?

Answer 11

dont solve now .. just simplify

Answer 12

5/x^2-1 x+2/1???

Answer 13

\[\LARGE{\frac{5}{x^2-1}=\frac{4x+2}{x^2+1}}\]

Answer 14

like this

Answer 15

now : \[\LARGE{5(x^2+1)=(4x+2)(x^2-1)}\]
\[\LARGE{5x^2+5=4x^3+2x^2-4x-2}\]
can u solve it now?

Answer 16

this is what i got: 3x^2+7=4x^3-4x

Answer 17

@mathslover

Answer 18

ok .. so now solve it ..
:
3x^2+7 = 4x^3-4x
0=4x^3-3x^2-4x+7

4x^3-3x^2-4x+7=0

solve it (cubic equation)