Question

Find the vertex of the graph of the function.

f(x) = (x - 10)^2 - 8

Answer 1

Compare it with:

\[f(x) = (x - h)^2 + k\]

Can you tell me on comparing what is in place of h and k in your question ??

Answer 2

h is -20
k is is -8

Answer 3

k is right..

But how you got h = 20 ??

Just compare..

Answer 4

u just differentiate that

Answer 5

i mean 100

Answer 6

Why are you squaring??

Answer 7

idk i have to?

Answer 8

Need not to do anything..

Just compare them..

Answer 9

ok so its - 10

Answer 10

Little mistake..

Answer 11

:-/ ok vertex is jus the xtreme value may be max or min since tha function is always incresing nd has no upper bound xtreme shud be minimum........nd the smallest value is @ x = 10

Answer 12

10

Answer 13

You have compared x with x, - with - and h with ???

Answer 14

Yes now you are right..

Answer 15

So:

\((h,k) = (10, -8)\)

This is the required vertex..

Answer 16

wat do i do next

Answer 17

You have found the vertex that is what question is asking to find..

Answer 18

thanks :)

Answer 19

thats it

Answer 20

Yeah that is it..

Remember the equation I have given above..

That will help you to solve other problems too..

Answer 21

ok :)