A circle has a radius of 3 units and a center (1,-2). Find the equation of the tangent line at the point (5,-2). write the equation in slope intercept form

Question

amistre64 · Answer

dejavu :)

amistre64 · Answer

this would prolly make better sense to you if the points did not form a horizontal line to begin with ....

anonymous · Answer

Yes i think it would but im still confused and been trying to find a video and extra help like crazy

amistre64 · Answer

show me what you understand it as, right or wrong ....

anonymous · Answer

Ok well i understand that you have to find the slope but then after it i am like oh no

amistre64 · Answer

do you understand, that in a circle; the tangent line to the circle is perpendicualr (90 degrees) to the line created by center and the point that interests us?

anonymous · Answer

Yes and it only touches the circle once

amistre64 · Answer

good, the only other thing to understand is how to define the equations of a horizontal, or a vertical, line in this case

amistre64 · Answer

lets start with the crossing axises|dw:1343767456155:dw|

anonymous · Answer

Ok i see

amistre64 · Answer

a horizontal line will only pass thru one point on the y axis; so its 
equation is defined as:  y = ___ , whatever value the y needs to be to satisfy the point|dw:1343767560095:dw|