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Find the product of the complex number and its conjugate. 1 + 3i Answer : 1 - 9i correct??
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multipy that and 1-3i
so yu will get 10
was gonna say that :P
whatever katie... lies.
thank you
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welcome. anytime.
i was typyin was i not :P
In general (a+b)(a-b) = a^2-b^2 So (1+3i)(1-3i) 1^2 - (3i)^2 1 - 9i^2 1 - 9(-1) 1+9 10 which means (1+3i)(1-3i) = 10
thanks @jim_thompson5910
you're welcome
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