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Solve: 10^x=1/3
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pp 227 http://finedrafts.com/files/Larson%20PreCal%208th/Larson_Precalculus_8th_txtbk.pdf
how do you think you can bring down the x? what operator do you need to use?
try it in a calculator, hal
so does x=30
\[10^{30}=1/3 (are you sure???)\]
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am calling it a day . going to eat and sleep . sorry if confused you.
you didn't confuse me. you confused yourself :)
so x=2.095
ok . solve it.
x = -(log(3))/(log(10)) x=-0.477121
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i got x=0
how did u get the negative 9
i mean 0
ok 10^x = 1/3 Take the logarithm to the base 10 of both sides: x = -(log(3))/(log(10)) x=-0.477121
ok i get it
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