Question

How do I integrate 8sin(x)(cos(cos x))dx ?

Answer 1

is this read as \[\int 8\sin x \cos (\cos x)dx\]

Answer 2

interesting...

let u = cos x
du = -sin x

\[\implies -8 \int \cos u du\]
that should be easier now

Answer 3

Thank you. that does make sense. It just confused me because of the cosine function! So -8sin(u) + C. I did that in my head, so sorry if there's some mistakes. But yes, the cosine function threw me off.

Answer 4

dont forget to change u back into cos x;)

Answer 5

Thank you so much! And I wont. :)

Answer 6

welcome ^_^

Answer 7

that integral almost breaks the wolf lol
http://www.wolframalpha.com/input/?t=crmtb01&_=1343799917386&i=integral+8sinx*cos(cosx)dx&fp=1&incTime=true

^^^this only worked with extra computation time

Answer 8

Yes, it timed out when I tried it, lol