How do I integrate 8sin(x)(cos(cos x))dx ?

Question

lgbasallote · Answer

is this read as $$\int 8\sin x \cos (\cos x)dx$$

lgbasallote · Answer

interesting...

let u = cos x
du = -sin x

$$\implies -8 \int \cos u du$$
that should be easier now

anonymous · Answer

Thank you. that does make sense. It just confused me because of the cosine function! So -8sin(u) + C. I did that in my head, so sorry if there's some mistakes. But yes, the cosine function threw me off.

lgbasallote · Answer

dont forget to change u back into cos x;)

anonymous · Answer

Thank you so much! And I wont. :)

lgbasallote · Answer

welcome ^_^

turingtest · Answer

that integral almost breaks the wolf lol http://www.wolframalpha.com/input/?t=crmtb01&_=1343799917386&i=integral+8sinx*cos(cosx)dx&fp=1&incTime=true ^^^this only worked with extra computation time

anonymous · Answer

Yes, it timed out when I tried it, lol