Question

What is the third–degree polynomial function such that f(0) = –24 and whose zeros are 1, 2, and 3?

Answer 1

its really just a matter of setting up the product using the zeros as bait; then scaling it such that f(0) = -24

Answer 2

to tell you the truth i really dont know

Answer 3

given a root, the set up is such that:

x - n = 0; when x=r; n=-r

set up 3 products using the roots

(x-1)(x-2)(x-3)

now, determine your scalar by making x=0

a(-1)(-2)(-3) = -24

a(-6) = -24; when a=4

4(x-1)(x-2)(x-3) should do it

Answer 4

okay

Answer 5

well these are the possisble answers
f(x) = 4x3 – 24x2 + 44x – 24

f(x) = 2x3 – 24x2 + 22x – 24

f(x) = 4x3 + 24x2 – 44x – 24

f(x) = 2x3 + 24x2 – 22x – 24

Answer 6

can you narrow it down any?

Answer 7

if anything, copy the solution i gave you into the wolf and see how it expands it ....