Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

PLEASE HELP... IM STUCK... Part 1: Describe the graphs of the functions f(x) = 2^x – 1 and g(x) = –2^x – 1. Part 2: Compare and contrast the domain and range of f(x) and g(x).

OpenStudy (anonymous):

Seems they are both exponential functions. f(x) is a growth function that has been lowered one unit. g(x) is a reflection of f(x) about the line y=-1. As exponential functions, the domain of both functions is all real numbers. The range of f is (-1, infty), while the range of g is (-infty,-1).

OpenStudy (anonymous):

can you explain that a little bit simpler? i dont understand! :( IM SORRY!

OpenStudy (anonymous):

Exponential growth functions like 2^x are always positive. They start very near zero for values of x that are very negative, are one for x = 0, and get very large as x becomes more positive. If we subtract one, it moves the whole graph down one. That will give us f(x). On the left tail (as x goes to negative infinity) the function gets very close to -1. At x=0, the function is zero, and as x becomes larger and positive, the function grows rapidly.

OpenStudy (anonymous):

g(x) starts with the same basic function as f(x), but it is reflected about the x axis (turned upside down, if you will), then moved down one. If you plot f(x) and g(x) on the same graph, they will appear to be the mirror images of one another around the line y=-1.

OpenStudy (anonymous):

The domain of exponential functions is all real numbers. That means we can plug any value of x into the function, and still get an answer. The range of the functions are the values of y that are generated by plugging in all the values of x. In the case of f(x), the values of y are always bigger than -1. In the case of g(x), the values of y are always smaller than -1.

OpenStudy (anonymous):

Oh o know i understnad your first comment! :P is that the answer?

OpenStudy (anonymous):

Pretty close.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!