Circles M and K are congruent and QR ≅ LN . Find QR.
if the circles are congruent, then they have equal radii
so if M is the center of circle M and K is the center of circle K, then MQ = KN
Similarly, we can show that MR = KL
see where this is going?
it can be solved by putting both the arms equal and therefore x= 8 now you can find QR
its given that l(QR) = l(LN). which implies that 5x - 7 = 3x + 9 solve this eq to get the value of x. then substitute it in 5x-7 and u'll find the length of QR.
5x-7=3x+9 -3x -3x ?
sure. u can proceed that way. so now u have, 2x-7=9. now add 7.
2x-7=6x?
i mean 9x?
no. it'll only be 9. not 9x. u're exp is this: 3x + 9 - 3x..............what will this give u?
5x-7=3x+9 -3x -3x 3x + 9 - 3x add 3x?
no no...see, u're subtracting 3x from both sides right? so what u're doing is LHS: 5x-7 - 3x ------ 2x - 7 RHS: 3x + 9 - 3x ----------- 9 u got it?
that is rhs and lhs i confused
LHS = left hand side of the eq RHS = right hand side of the eq.
still confused?
5x-7 =3x + 9 - 3x -3x 2x - 7+9
oh gosh!! @coolaidd take an attempt to solve it your own....it will be easier!!
how about you stop commenting on my post..clearly i am working thorugh it..this is between me and @Vaidehi09
thanks..
yes u got it ryt this time. so now u have 2x-7 = 9, right?
yes..do i add 7?
yup. go ahead.
5x-7 =3x + 9 - 3x -3x 2x - 7+9 +7 +7 2x=16 2 2 x=8
okay @coolaidd my apologies i didn't mean it that way...
yea, that's it!
@coolaidd so now just sub the value of x and find out l(QR).
thanks!
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