A circle has its center at (-2, 5) and a radius of 4 units. What is the equation of the circle?

(x + 2)2 + (y - 5)2 = 16

(x + 2)2+ (y + 5)2= 16

(x + 2)2+(y - 5)2 = 4

(x - 2)2+(y + 5)2 = 4

Question

A circle has its center at (-2, 5) and a radius of 4 units. What is the equation of the circle?

 (x + 2)2 + (y - 5)2 = 16

 (x + 2)2+ (y + 5)2= 16

 (x + 2)2+(y - 5)2 = 4

 (x - 2)2+(y + 5)2 = 4

anonymous · Answer

Someone please help! Please?

anonymous · Answer

I am guessing it's the third answer that I provided, but I am second-guessing myself. Am I right, in the first place? Or am I right to second guess myself?

campbell_st · Answer

the general form of a circle is 

$$(x -h)^2 + (y - k)^2 = r^2$$

(h, k) is the centre and r is the radius

in your question you have a centre (-2, 5) and r = 4

substitute to find your equation

anonymous · Answer

oh.... ok. sorry. I forgot until u mentioned it. THANK U SO MUCH!!!!!

campbell_st · Answer

hope it helps

anonymous · Answer

:)