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Mathematics 21 Online
Parth (parthkohli):

Is there even a way to graph \(\imath\)? I believe that the answer to that is no.

Parth (parthkohli):

\(\imath\) as in \(\sqrt{-1}\).

OpenStudy (anonymous):

Yes, you can graph it.

OpenStudy (unklerhaukus):

what is \[\imath\] \(\hat\imath\) is the unit vector in the x direction

Parth (parthkohli):

Hmm. I meant the \(i\).

Parth (parthkohli):

The complex number.

OpenStudy (anonymous):

|dw:1343879534849:dw|

OpenStudy (unklerhaukus):

well you have used the wrong symbol, the imaginary unit has a dot \(i\)

Parth (parthkohli):

I have heard of a complex plane, but can we graph it on a normal graph? The Cartesian one.

OpenStudy (unklerhaukus):

you'll need an Argand diagram Parth

Parth (parthkohli):

Ok. I'd now be posting another question related to the complex plane.

Parth (parthkohli):

Argand Diagram?

OpenStudy (unklerhaukus):

the normal cartesian graph dosen't have an imaginary direction

Parth (parthkohli):

Knew it!

OpenStudy (unklerhaukus):

Argand diagram is just complex plane

OpenStudy (anonymous):

If you're in America, they likely don't call it the "Argand Diagram" in anything pre-Engineering.

OpenStudy (unklerhaukus):

fortunately im not in america

OpenStudy (anonymous):

...yes, it's tragic.

OpenStudy (anonymous):

I get "What the heck is an Argand diagram" repeatedly...

Parth (parthkohli):

Haha, me neither. I'd have been this kid who would've been hanging out with other kids all the time; nothing constructive.

OpenStudy (anonymous):

The distinction is to note that it is "like" a cartesian plane, but it IS NOT a cartesian plane. In that where 'y' is real, 'i' is NOT real.

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