if csc^-1x = sin^-1(1/x) then is sin^-1 = csc^-1(1/x) ???
please help me!!
is that a question ?
yes i was wondering if this is right
i want to rewrite y=csc^-1x to sin but i dont know..
kk ! I'll ask you a question : what is the domain of the function \[\csc^{-1}\]
x≤-1 or x≥1
now if \[x \ge 1=====>\frac{1}{x}\text{ ?????? } \] ?!
\[\left(\begin{matrix}1 \ \div \ x≥1\end{matrix}\right)\]
Now I'm lost ! what did you prove ! this \[\csc^{-1}(x)=\sin^{-1}(\frac{1}{x})\] ?!
i just want to know if this is correct but i dont know how to solve when sin^-1(x)
Sorry im confusing you:(
No !No ! problem at all ! let's discuss about that ! what you diid is correct...If \[x \ge 1 \text{ or } x \le -1 \]
it can be any numbers right? x≥1 or x≤−1
Yes ! So, keep this in your "japanese " mind if we have to write i(or type) \[\csc^{-1}(***)\text{ then (***) should be } *** \ge 1 or ***\]
*** less than -1 ! now let's return back to your question !
hmmm...? im lost i tried this out is it right?
It seems correct ! But It's not ! You did the biggest mistake of your life ! that what I was saying ! You should be careful ! if \[\csc^{-1}(x)=\sin^{-1}(\frac{1}{x})\] then \[x \le-1 \text{ or }x \ge 1 \] we're asked :if \[\csc^{-1}(\frac{1}{x})=\sin^{-1}(x)\]
then \[\frac{1}{x}\text{ should also satisfy } \frac{1}{x} \le -1 \text{ or } \frac{1}{x} \ge 1 \]
is that possible ?
@lsugano
.......i am so lost :( okay ill try to make it clear again and write it on my tablet and if possible please checkk!!
kk ! you don't know yet if the statement : if csc^-1x = sin^-1(1/x) then sin^-1(x) = csc^-1(1/x) is correct or not !
yes! so i was wondering if this is correvct?
We are looking for an answer together :) :) !
so is this statement true?
both !
True if x=1 false if x=/= 1
false if x is not 1 you mean?
yes !
so what if it was more than or less than 1?
for all numbers ?
yes
then it will be false certainly !
can you prove that to me ?!
idont know how....>< this is confusing me
:'( :'( ! I've just explained it to you ! all of this is about the domain !
wait i think i got it! so my main goal is to understand the inverse secant cosecant and cotangent of the functions!
:) :) use your Tablet ! and prove that to me !
are you doing that ?
im almost done with csc!
kk ! I'm waiting...Take your time !
i got tan!
Another Question ?
imeant cotagent!!
It wasn't csc^-1 ?!
im trying to find all three i also found csc^-1
take a look at this !
what does the arrows stand for?
\[\text{statement A} <=====>\text{statement B}\] means statement A is equivalent to Satement B
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