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Mathematics 17 Online
OpenStudy (unklerhaukus):

simplify \[\text{sgn}(i)\]

OpenStudy (kinggeorge):

To my understanding, \[\text{sgn}(i)=\frac{i}{|i|}=\frac{i}{1}=i\]

OpenStudy (dominusscholae):

^On Mathematica, it does return this.

OpenStudy (dominusscholae):

sgn (x) = \[x/\left| x \right| \] for all numbers.

OpenStudy (unklerhaukus):

\[\text{sgn}\left(\frac1i\right)=\]

OpenStudy (kinggeorge):

\[\frac{1}{i}=-i\implies\text{sgn}\left(\frac{1}{i}\right)=-1\]

OpenStudy (unklerhaukus):

are you sure KG?

OpenStudy (dominusscholae):

http://en.wikipedia.org/wiki/Sign_function

OpenStudy (kinggeorge):

\[\frac{1}{i}\cdot\frac{i}{i}=\frac{i}{-1}=-i\]\[\text{sgn}(-i)=\frac{-i}{|-i|}=\frac{-i}{1}=-i\]So unless I'm severely misunderstanding the definition of \(\text{sgn}\), I'm pretty sure.

OpenStudy (unklerhaukus):

that right but thats different to your last post

OpenStudy (dominusscholae):

@UnkleRhaukus follow the Wikipedia link above dealing with this.

OpenStudy (kinggeorge):

Oops. I had a typo the first time I typed it. :(

OpenStudy (unklerhaukus):

i see

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