solve
sure
\[c _{18 12}\]
?
c=0
judging from your past questions...this has something to do with arithmetic/geometric sequence?
is that a wolfram answer again?
yeah it does
@katiebugg Please don't post a new question until you are done with your previous one. Thanks :)
sorry i got the answer
i still dont get what this question means...and why the heck do people LOVE attaching "thanks" at the end of their statements o.O
i dont get it eaither... the question that is
@katiebugg I can see that you've posted similar questions. Did you understand the concepts involved?
@lgbasallote to sound polite thanks:)
kinnda butt not really been upp all night doing this soooo
dont use it on me -_- it creeps and freaks me out
hahaha
@katiebugg are there any other conditions or phrases that come along with the question?
@katiebugg it's better to take rest now and start afresh tomorrow.
nope juse evaluate
and this has to bee done 2mrw sooo
can you write it in bigger text?
its a C then 18 and 12
but where are 18 and 12..beside C? below C? some of the placements are VERY important
umm subscripts
@katiebugg are you learning combinations?
yess!!!!!!
OH...that makes more sense =_=
sorry
\[\huge nCr = \frac{n!}{r!(n-r)!}\] does that help?
ahhhhhhhh!!!!!!!! no
for example \[3C2 = \frac{3!}{2!(3-2)!}\]
now does it help?
this is last one then get to go to bed and no ima still lost :(
here's another one... \[12C10 \implies \frac{12!}{10!(12-10)!} \implies \frac{12!}{10!2!} \implies \frac{12 \times 11 \times \cancel{10!}}{\cancel{10!} 2!} \implies \frac{12 \times 11}{2 \times 1}\] does that help?
how do i know were the 18 and the 12 go
the bigger one is always in the numerator
that's just how i remember it heh
k thaks!!!!!!!!
welcome ^_^
spamming random examples of solutions really does help huh...
:( no i got like the first step and now ima lost
oh btw....you're online schooled right?
just for summer i wanted to jump ahead soo i took a class
hah i knew it..i could tell based on the random jumping of topics haha lol...anyway back to your question
what did you get for the first step?
umm 18/12(6)
hmmm you do mean \[\frac{18!}{12!6!}\] right?
and u watchin my questions hahah creeper :P and yess
the exclamation points are very crucial...
heh it's my avatar duty :p
love that show ahahaha
okay here's a hint for you \[\small 18! \implies 18 \times 17 \times 16 \times 15 \times 14 \times 13\times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\] \[12! \implies 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\] \[6! \implies 6 \times 5 \times 4 \times 3 \times 2 \times 1\] does that help?
just told me what the !!! do right
hmm?
okay here's another hint \[\large \frac{18!}{12! 6!} \implies \frac{18 \times 17 \times 16 \times 15 \times 14 \times 13 \times 12!}{(12!)(6!)}\] does that help more?
look for something you can cancel..
and then
cancel the cancellable
ok i think
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