Solve by completing the square.

.05x^2-x+1=y

Question

Solve by completing the square.

.05x^2-x+1=y

anonymous · Answer

No.  There is no completing the square method there.

anonymous · Answer

steps
(0.05 x-1.) x+1 = y
(0.223607 x-4.23607) (0.223607 x-0.236068) = y
0.05 x^2-x-y+1 = 0

anonymous · Answer

u can ask someone else for me also not getting

anonymous · Answer

Okay.

anonymous · Answer

satellite73 is best in maths u can call him

anonymous · Answer

Okay, thanks.

lgbasallote · Answer

divide everything by 0.5 first

anonymous · Answer

you can complete the square, first multiply by 2

lgbasallote · Answer

the coefficient of x^2 needs to be 1 only so you need to divide by 0.5

or in other words...multiply by 2 :|

anonymous · Answer

in order to complete the square, the first step is to make sure the leading coefficient is 1

anonymous · Answer

what @lgbasallote  is saying

anonymous · Answer

on the other hand, now that i look at the question, it reads 
$$.05x^2-x+1=y$$ not 
$$.05x^2-x+1=0$$ so it is not clear what "solving" means in this context

anonymous · Answer

and on further reading, i see that it is  $.05$ and not $.5$ so you would need to multiply by 20 not 2

anonymous · Answer

that is if you wanted so solve 
$$.05x^2-x+1=0$$  for $x$ by completing the square, the first step would be multiply by 20 to make the leading coefficient 1 and write 
$$x^2-20x+20=0$$ then 
$$x^2-20x=-20$$
$$(x-10)^2=-20+100=80$$
$$x-10=\pm\sqrt{80}=\pm4\sqrt{5}$$
$$x=10\pm4\sqrt{5}$$

anonymous · Answer

x= any - number, y=0.05x^2-x+1