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Can anyone help me solve the following trig question? Show that sin(40)+sin(20)=cos(10)
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use this identity \[\sin p+\sin q=2 \sin \frac{p+q}{2} \ \cos \frac{p-q}{2}\]
Hmm I got 2sin(30)cos(10) But I still got the 2 sin(30)
well \(\sin 30=\frac{1}{2}\)
Oh I see I overlooked that thanks.
yw :)
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