Jerry inscribed a quadrilateral ABCD in a circle, as shown below. If the measure of arc BCD is 250°, what is the measure of angle BCD? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0800_Subtest_01_06/image0024e67730b.jpg
I need someone to explain to me how to solve it. I don't need the exact answer.
Hint: Find the measure of arc BAD
stop cheating on your virtual school. i am in geomatry honors with mrs boo
im jus here to help
As long as this is not a test, I think she is perfectly fine with getting help.
No one asked you. I'm not cheating I'm asking for help.
So would I do 360-250?? I just don't get this..
Yes, correct. Arc BAD = 360 - 250
wait, @Hero, isn't the whole quadilateral meant to equal 360?
weird?
No the circle equals 360. But why do I need the other arc measure?
You need to find arc BAD because angle BCD cuts across it.
So it would be 110 and then I cut it in half to get the angle measure?
Correct
Wow, a student who could actually follow my hints. Looks like @tiffybabyy really did come here for help.
So the answer is 55. Awesome! Thank you Hero, you truly are mine (:
@hero, isn't the angles in a quadilateral inscribed by a circle equal to 360?
Yes @JayDS, Add 250 + 110 and see what you get
but wat about and B and D?
We only needed to find angle BCD
@tiffybabyy, it seems that u do not know the property of a quadrilateral.
@JayDS, I know you're excited, but we only needed to find one angle.
but I want to know how it would work since C+A=360 already?
it should be A+B+C+D=360?
Those were the measures of the arcs of the circle, not the angles of the quadrilateral.
Don't confuse arcs with angles @JayDS
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