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Mathematics 16 Online
OpenStudy (anonymous):

If a # b is defined as the average of a and b, what is the value of 2 # 4 # 9? (a) 3 (b) 5 (c) 6 (d) 7.5 (e) 18

OpenStudy (lgbasallote):

wont it just be the average of those three?

OpenStudy (lgbasallote):

\[\huge \frac{2 + 4+ 9}{3}\]

OpenStudy (anonymous):

the average is a+b+c/3 so it's 2+4+9/3= 5... but that's not the answer choices what's b?

OpenStudy (anonymous):

sorry i didn't notice that my answer choices came out weird but thanks. i didn't think it was going to be that simple but i guess it is.

OpenStudy (anonymous):

no problem! :D

OpenStudy (anonymous):

although I thought an alternative solution would be finding average of 2 and 4 then using that answer to find the solution between that and 9... but maybe I'm overthinking it loll if we do it that way then it's c

OpenStudy (anonymous):

yeah that's what i tried doing first

OpenStudy (anonymous):

hmm that can be it... idk how difficult is the problem supposed to be if it was really easy I would pick 5 but if it's supposed to be hard then I would pick 6

OpenStudy (anonymous):

yeah it's an sat question. sometimes they're really easy and other times they're really hard but i think i'm gonna stick to c.

OpenStudy (anonymous):

lets try it

OpenStudy (anonymous):

average of 2 and 4 is 3 average of 3 and 9 is 6

OpenStudy (anonymous):

Loll I knew it was an SAT question , I was just about to ask you that.. is it the beginning of the test or at the end?

OpenStudy (anonymous):

beginning lol

OpenStudy (anonymous):

oh haha well it's supposed to be easy. But yeah c would be your best choice

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

now maybe we try it the other way average of 4 and 9 is 6.5 average of 2 and 6.5 is 4.25 so i guess this is not associative it matters what you do first

OpenStudy (anonymous):

yeah i think so and that's not an answer choice either

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