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Check if \(2^{12} - 1\) is divisible by 13. Can I use Fermat's Little Theorem here?
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I get yes as the answer. \(2^{13 - 1} - 1 \) if you rephrase it. Back to the definition of the theorem: \(a^{p - 1} - 1\) is divisible by \(p\). Am I right?
Here, \(p = 13\).
three one five?
?
he means \(315\) as the answer
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I just wanted to check if it was divisible.
Oh yes, then it is divisible!
yeah; you can use induction as well i think
Why use induction? There is no \(k\) or \(n\) or \(x\) here.
Well so I was correct, wasn't I?
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i know lol change the 12 into n you are correct anyway but dont trust me
Well, now as I have an integer quotient, I must be correct.
yeah lol. no medal is needed for me; i didnt do anything
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