a raindrop of mass $3/35 \times 10^{-5}$ kg falls vertically at constant speed under the influence of gravity and air resistance. Model the drop as a particle. As it falls 100 m, what is the work done on the raindrop (a) by the gravitational force an (b) by air resistance?

please explain this to me step-by-step NOT in one whole solution in one post...

Question

a raindrop of mass $3/35 \times 10^{-5}$ kg falls vertically at constant speed under the influence of gravity and air resistance. Model the drop as a particle. As it falls 100 m, what is the work done on the raindrop (a) by the gravitational force an (b) by air resistance?

please explain this to me step-by-step NOT in one whole solution in one post...

lgbasallote · Answer

im thinking $$\Large (a) \; \;W_{GRAV} = -\Delta U_{GRAV} = -(m)(g)(y_2 - y_1) $$$$\Large \implies -(3.35 \times 10^{-5})(9.8)(0-100)$$
is that right?

lgbasallote · Answer

@Valpey you're good in physics right?

lgbasallote · Answer

then i think air resistance is just negative of that..

anonymous · Answer

if resistance would be equal and negative the drop would be hanging in air then and make a rainbow out of it ;)

lgbasallote · Answer

really?

anonymous · Answer

I'm sorry, but @theyatin is wrong. Just because there is no net force on an object, doesn't mean it has to be at rest--it can also move at a constant velocity w.r.t an inertial observer.

Now, coming to the question, @lgbasallote, you are absolutely right in your understanding & the first & the third reply of yours answers the question. A medal for you for that!!

lgbasallote · Answer

yay thanks for confirming!

anonymous · Answer

yw. :)

anonymous · Answer

then may you please explain how water drops hang in the air i am curious to know. . .