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The equation 3^(x-1) + 5^(x-1) = 34 has hw many solutions?
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how about u solve it bro
No idea lol,
use wolfram
No...wolfram
if \(x>3\) then \( 3^{x-1} + 5^{x-1}>9+25=34\) if \(x<3\) then \( 3^{x-1} + 5^{x-1}<9+25=34\) only answer is \(x=3)
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hm....the answer should be no solution!
but \(x=3\) satisfies the equation
@mukushla Can u expl ur method...
\(3^x\) and \(5^x\) both are increasing functions...
any other method such taking ex x-2 =t like that
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yep ... that's the only way i know ... analytic approach
.the answer should be no solution!
impossible ....... let \(x=3\) then \(3^{3-1} + 5^{3-1}=3^2+5^2=9+25=34\)
May be my book is wrong! thxx
lol
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also...lol..:D
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