$$\mathcal L^{-1} \left\lbrace \frac{3s+1}{s^2 + 6s + 13} \right\rbrace$$

i got $$e^{-3t}(3\cos 2t - 4\sin 2t)$$
can anyone check?

Question

$$\mathcal L^{-1} \left\lbrace \frac{3s+1}{s^2 + 6s + 13} \right\rbrace$$

i got $$e^{-3t}(3\cos 2t - 4\sin 2t)$$
can anyone check?

experimentx · Answer

lol .. use the same trick
make partial fractions ... and plug it into WA

lgbasallote · Answer

wolfram gave some weird answers...

experimentx · Answer

make partial fractions first

lgbasallote · Answer

then?

experimentx · Answer

ask for inverse laplace transfrom individually ... WA is clever ... always interprets the input in such a way that it would take least running time

experimentx · Answer

my suggestion ... also provide the expression in text as well as latex. so that it's easy to copy paste!

experimentx · Answer

lgbasallote · Answer

that's why i said i was weird

experimentx · Answer

it doesn't have partial fractions ...  try to factorize the denominator ... you might get imaginary values.

lgbasallote · Answer

i just did $$\frac{3s+1}{(s+3)^2 + 2^2}$$

experimentx · Answer

Hmm ...|dw:1344083615186:dw|