Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 4, -8, and 2 + 5i
use the fact that an n'th degree polynomial with roots \(x=r_1,x=r_2,...,x=r_n\) can be written as:\[f(x)=C(x−r_1)(x−r_2)...(x−r_n)\]where C is some constant. in addition, if a polynomial has any complex roots, then they ALWAYS appear in pairs where each pair contains a complex number and its complex conjugate. example: if a polynomial has roots 4 and 1+2i, then we can write it as:\[f(x)=C(x−4)(x−(1+2i))(x-(1-2i))\]since (1-2i) is the complex conjugate of (1+2i)
would this be right f(x) = x4 - 6x3 + 20x2 - 122x + 928
no, it is not. Following what @asnaseer told you, you should multiply \[ \large (x-4)(x+8)(x-(2+5i))(x-(2-5i)) \]
f(x) = x4 - 19x2 + 244x - 928
yes, well done
a tip for complex roots: first write it as x = 2 +- 5i then get the imaginary part alone x-2 = +-5i square both sides (x-2)^2 = 25i^2 simplify x^2 -4x +4 = -25 set equal to zero x^2 -4x +29 = 0 --> (x-4)(x+8)(x^2-4x+29)
nice tip @dumbcow :)
and well done @babydoll332 :)
thank you
yw :)
thank you guys as well :D
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