Question

Solve. x^2 = 6x – 6

x = 3 ± sqrt.3

x = 6 ± sqrt.3

x = 3 ± sqrt.30

x = 3 ± sqrt.6

Answer 1

rewrite the equation will all terms of the left.

the general form of a quadratic is

ax^2 + bx + c = 0

and the general quadratic formula is

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

you need to identify a, b, c and then substitute and evaluate

Answer 2

I substituted the terms into the quadratic formula but I have no idea what to do from there or how to go about solving it..

Answer 3

you just need to evaluate it...

Answer 4

I got -6x+/- sqrt.6^2-4x^26/ 2x^2

Answer 5

well you need to know.... a,b and c are coefficients... do you know that term...?

Answer 6

yea i herd it before..

Answer 7

do you know what it means...?

Answer 8

as an example if you have

\[5x^2\]

5 is the coefficient and x is the pronumeral

Answer 9

so you need to identify the values a, b, c the coefficients

Answer 10

ok so a would be 1, b would be 6 and c would be -6?

Answer 11

no... you need to rewrite the equation so it is equal to zero

\[x^2 - 6x + 6 = 0\]

then identify a, b, c..... substitute and evaluate

Answer 12

so a=x^2, b=6x and c=6?

Answer 13

the anwer is 3 +/- sqrt of 3

Answer 14

no a = 1, b = -6 and c = 6

your answer is correct.