Solve the following equation: x-6=7(x-3)
Where are you having a problem?
well im not sure what i do first
PLZ @ParthKohli help him
PLZ NOBODY ANSWER EXCEPT @ParthKohli
You should start by distributing in the right-hand side.
Have you heard of the distributive property?
yes
So can you distribute 7 into \(x - 3\)?
im not sure
Hint:\[7(x - 3) \implies 7(x) - 7(3) \]
yes it can be
So simplify \(7(x) - 7(3)\), please?
be comes 7x-21
Yep. Now, we have\[x - 6 = 7x - 21 \]Everybody hates Math, so we have to perform some magic to get \(x\) on one side and the rest of the friends on other.
\(x\) is not liked by people, and we have three friends:\[x - 6 = 8\]We'll add 6 to both sides\[x - 6 + 6 = 8 +6 \]Because \(-6 + 6\) is zilch, we'd just cancel it out because it doesn't make sense to keep extra numbers when you could just remove them.\[ x = 8 + 6\]\[x = 14 \]
That was just an example, anyway. What you have to do is get the \(x\) alone on one side.\[x - 6 = 7x - 21 \]Think of some possible ways you could do so.
Hint: You may add 6 to both sides :)
dont it become x=7x-15?
Yeah, it does. Now what you gotta do is get the -15 alone too, because you want an answer like\[x = \text{some number} \]
Can you subtract 7x from both sides?
yea and you get 6x=-15 , i think
You were almost right.\[x - 7x = -15 \]\[ -6x = -15\]Notice that negative sign there.
ooh, i thought it was negative but i wasnt sure, but dont i divide -6 nd -15
Yes, you do. But you can make it easier by cancelling the negative from both sides:\[\cancel{-}6x = \cancel-15\implies 6x = 15 \]
Now you divide 6 from both sides to get \(x\) alone.
which makes x=2.5
Yes, that is right.
thanks alot :D
I have some things for you to note. Are you busy?
Okay. Gotta have food. Will message you in some time :D
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