The flow chart proof with missing statements and reasons proves that if a line intersects two sides of a triangle and divides these sides proportionally, the line is parallel to the third side. Which statement and reason can be used to fill in the numbered blank spaces?
Given: In ∆ABC below,BD over BA equals BE over BC . Prove: segment DE is parallel to segment AC http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1002_03/image0024e983525.gif
Answers: 1. ∡BDE ≅ ∡BAC 2. Corresponding Parts of Similar Triangles 1. ∡BDE ≅ ∡BCA 2. Alternate Exterior Theorem 1. ∡BDE ≅ ∡BAC 2. Corresponding Angles Postulate 1. ∡BDE ≅ ∡BCA 2. Corresponding Parts of Similar Triangles I think its alternate exterior
since we are proving similarity by SAS so we must find a similar angle between the two triangle and since B is same for both it can be used in the proof so the answer is 1 ∡B ≅ ∡B 2 Reflexive Property of Equality
That's not one of the answers though?
it's the last option. .. 1. ∡BDE ≅ ∡BCA 2. Corresponding Parts of Similar Triangles
Nope its not, already tried that one
please help!
Its not alternate angles either.
converse of corresponding-angles postulate is : if corresponding angles are congruent, then the two lines are parallel
look at the triangle pix, since they are similar, corresponding angles of similar triangles are congruent : ∡BDE ≅ ∡BAC
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