Write a recursive formula for 16, 9, 7, 2, 5....
what is 16-9?
7
What's the term after 9 in the sequence?
What is your hypothesis?
9-2=7 an 7-2=5
Hypothesis?
ok but how write the formula?
name the terms in your head
what is the relationship between successive terms?
when you subtruct the first number by the second you will get the third and so on
exactly the first two terms are just given after that the following terms are generated according to the pattern you just identified so call some number past the third number\[a_n\]how can we relate that number to the numbers preceding it\[a_{n-1},a_{n-2}\]?
an-7,an-2,an-5
I think you are misunderstanding the notation...
\[a_{n}\]is the nth number in the sequence\[16, 9, 7, 2, 5... \]\[a_1,a_2,a_3,a_4,a_5...\]so the number in the subscript is just telling you what term we are on now, what is the relationship between\[a_5,a_4,\text{ and }a_3\]?
subtracting 1
write out a formula for \(a_5\) in terms of \(a_4\) and \(a_3\)
how do I write a formula
try it with number let me make sure you understand what I am asking... what is \(a_5\) ?
5
yes, what is \(a_4\) ? what is \(a_3\) ? how are these three numbers ralated?
related*
4,3,2 they are decreasing as you go along by 1
no you have misunderstood\[a_1=16\]\[a_2=9\]\[a_3=7\]\[a_4=2\]\[a_5=5\]\[...\]the numbers in the bottom right (called subscripts) just tell you the term we are on
and will that be considered a formula
so in general when we write \[a_n=n^{th}\text{ term }\]to write a formula we need to generalize the relationship between any three numbers in the list, so no, listing out the given terms is how we start, not the answer
what is \(a_3\) ?
3
is it? what is the third term on the list?
7
yes what is \(a_2\) ?
9
yes what is \(a_1\) ?
16
now you're getting the idea now what is the relationship between those three numbers?
subtracting the first 2 to get the 3rd number
right now write that out mathematically (if you still can't do it with an then just write it out with the numbers....)
16-9=7,7-2=5
excellent now all you need to do is rewrite this with the \(a_n\) notation and the formula comes out instead of writing 16-9=7 write a_?-a_?=a_? fill the ?'s with the correct subscript (number of the term)
a-16=9=a-9=7=a-7=2=a-5
no, remember what \(a_1\) means what is \(a_1\) ?
if you can't write this using the equation editor write it as a_1=
16-a=9,9-a=7,7-a=2,a-2=5
what is a_1 ?
16
what is a_2 ?
9
what is a_3 ?
7
now you showed that 16-9=7 so rewrite the above expression with the a_n notation a_?-a_?=a_? (there should only be three terms)
a16-a9=a7
16 is not a16 16 is a_1
a16 would be the 16th term of the sequence (we don't know what that is yet) you are over complicating the situation. all I want you to do is recognize the terms which you just did a moment ago
fill in the other two numbers 9=a_? (it's \(not\) a_9, it's the number of the \(term\))
a_1-a_2=7 a_3_a_4=2a_3-a_4=5
almost, but please don't write it all in a line like that, it is hard to read.... if you started writing a_1-a_2=7 that is good, but you still need to sub for 7=a_?
what do you mean couldn't write like the way I wrote
did you try to write a_1-a_2=7 a_3-a_4=2 a_3-a_4=5 ??? if so that is not quite right, we want no numbers left just call everything by the term name
so what is term is 7 (a_(what number??)) a_1-a_2=a_?
3 term
so we can write a_1-a_2=a_3 understand??
yes
ok for the sake of simplicity let's turn this around a_3=a_1-a_2 now what about the other terms? a_4=? a_5=?
a_4=a_2-a_3
nice!
a_5=a_3-a_4
ok, so now you need to find a way to write this in general for a_n=?
whats n
to do this try calling n=5 what is the formula then? \[a_5=a_3-a_4\]let \(n=5\) \[a_n=a_?-a_?\]that is, how are the three subscripts related (if n=5 then 3=n-?)
n is the unknown n'th term in the sequence
that is, whatever term n they want will specified by our formula
ok so how do i write the formula?
like I say, try it with any three numbers\[a_4=a_2-a_3\]if we rename \(4=n\) how would we write 3 in terms of n ? (as 3=n-(something) ) i.e. 3=4-x
Join our real-time social learning platform and learn together with your friends!