Question

Some help please.....

Answer 1

\[\left( \sqrt{7} \right)^{x+4} = 49^{x}\]

Answer 2

x+4/2= 2x

Answer 3

(x+4)/2=2x

Answer 4

hint : try to make the bases equal and use

\[\huge\sqrt{7}=7^{\frac{1}{2}}\]and\[\huge49=7^2\]