Question

having trouble figuring out how to solve this. e^(x-5)=(1/e^4)^(x+2)

Answer 1

Try taking the ln of each side so you can get the exponents down.

Answer 2

so we have (x-5)ln e=(x+2)ln (1/4e^4)
after this what is our next step?

Answer 3

you have to be careful in simplification here\[(x^a)^b=x^{ab}\]and\[\frac1{x^a}=x^{-a}\]so\[\large (\frac1{e^4})^{x+2}=(e^{-4})^{x+2}=e^{-4(x+2)}\]now try with the log...

Answer 4

just got it. thx. mental block

Answer 5

-3/5?