A particle in a circle at 200rpm. If the frequency is increased to 400rpm in 2 min at a uniform rate the magnitude of angular acceleration is?

Question

anonymous · Answer

Final angular velocity = Initial angular velocity + angular accl .* time
Let x be the time,
400 = 200 + 2*x , x = 100 revolutions/min^2

anonymous · Answer

@kartiksriramk  wat we have to find in ur eq

anonymous · Answer

We have to find the angular acceleration.

anonymous · Answer

@kartiksriramk   wat should i do now

anonymous · Answer

The angular acceleration is the answer.That all.

anonymous · Answer

i have to solve for x

anonymous · Answer

400 = 200 + 2*x

anonymous · Answer

Yes.

anonymous · Answer

x =100

anonymous · Answer

is that the answer

anonymous · Answer

The option are      pie/100       pie/200         pie/36     pie/18

experimentx · Answer

just find the angular acceleration. final - initial / time ... and change those all into radians.

anonymous · Answer

well then you have to convert them into radians/second^2.

anonymous · Answer

It is pi/18. Multiply the answer by 2pi/60^2

anonymous · Answer

yup

anonymous · Answer

i gor it

anonymous · Answer

pie/18

anonymous · Answer

thxxx