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Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. x^2 − 4y^2 − 2x − 16y − 31 = 0
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http://www.wolframalpha.com/input/?i=x%5E2-4y%5E2-2x-16y-31%3D0 So I used Wolfram to plot it out for me, so it's an obvious hyperbola, but the q also asks to justify for full credit, so I guess there is some work involved....
compare it with .... http://en.wikipedia.org/wiki/Conic_section#Discriminant_classification you will know what it is. but by observation i can say that it's a hyperbola. because i can complete square , (x- h)^2 - (y-k)^2 = 0 <-- probably this is easier method ... but does not work sometimes.
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