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Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).
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SOMEONE HELP. PLEASE
First, your slope will be the reciprocal of the equation you have. So i'll take your equation that's in standard from and turn it into slope-intercept... So y=-3x+7 is the one you have now. The new equation will have the reciprocal; 1/3. Then you plug-in the coordinate (6,-1). So the equation that you are looking for should be y=1/3x-3. Or in standard form; -1/3x+y=-3!! :D
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