Question

What does it mean by restriced values in wolfram alpha?
http://www.wolframalpha.com/input/?i=integrate+1%2F%2810-v%2F5%29

Answer 1

where?

Answer 2

Click the show steps then you'll see it

Answer 3

im guessing it would be the value of v that would make the denominator equal to 0

Answer 4

you cant have a denominator of zero right?

Answer 5

That's weird because even the solution here
http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w11_ms_51.pdf
ended up
\[-5 \log (v-50)+c\]
but not
\[-5 \log \left(10-\frac{v}{5}\right)+c\]

Answer 6

hmmm wolfram does a lot of funny business =_=

Answer 7

um, v cannot equal 50. try evaluating your original expression with v = 50.

Answer 8

v can be 50, ln(0)=1

Answer 9

ln (1) = 0

Answer 10

ln (0) = infinity

Answer 11

ln e = 1

Answer 12

even your original function: 1/(10-v/5) what do you get when v = 50?

Answer 13

http://www.wolframalpha.com/input/?i=1%2F%2810-v%2F5%29

Look what would the integral be at v = 50?
v = 50 is a vertical asymptote.

Answer 14

how did you get ln (0) is infinity at @lgbasallote ?

Answer 15

hmm read the post lol...i didnt get ln (0) i was explaining that ln (0) is not 1

Answer 16

ln (0) is not infinity either

Answer 17

well...close enough

Answer 18

depends if 0+ or 0-...but i just generalized as infinity =))

Answer 19

my point was it's not 1 =_=

Answer 20

infinity is not close enough to negative infinity