Question

Simplify: (40a/b^2-5b+4) / (5a^2/2b-2)

Answer 1

40a / (b-1)*(b-4) / 5a^2 / 2(b-1)

40 cancels with 5 leaving 8
a^2 cancels with a leaving a in denominator

b-1 cancels with b-1

so left with

8/b-4 / a/2

invert and multiply

16/ab--4a

Answer 2

can you understand ? @jchavez96

Answer 3

Sorta , I'm working on it right now . @ashna

Answer 4

okay :)

Answer 5

These are my options ashna , I'm having trouble figuring it out .

Answer 6

@ashna

Answer 7

4th option is right , you want to know how , or do you know ?

Answer 8

@jchavez96

Answer 9

Can you explain it to me please ?

Answer 10

now take b^2-5b+4 and simplify it
like u do spliting the middle term
so....b^2-5b+4
b(b-4)-1(b-4)

Answer 11

(b-1) (b-4)

Answer 12

now {40a/(b-1)(b-4)}/{5a^2/2b-2}

Answer 13

take the main denominater in reciprocal form
then cancel 40a with 5a^2

Answer 14

now 16b-16/(b-1)(b-4) = 16(b-1)/(b-1)(b-4)

Answer 15

cancel b-1
u'll get opt4

Answer 16

(i.e) = 16/b-4

Answer 17

@jchavez96 understood now ?

Answer 18

I see . . . Thank you !! What is the b=4 for ? The one with the equal sign crossed out ?

Answer 19

@ashna

Answer 20

dat's b not equal to 4
just substute b as 4
u wont get correct answer

Answer 21

understood @jchavez96

Answer 22

Yes ! Thank you @ashna ! I really appreciate it !

Answer 23

no mention :)