When expanding ln to a fraction, do you only distribute it to the numerator?
\[a\times\frac{b}{c}=\frac{ab}c\]
Okay, great, thank you!
or you "could" go \[a\times\frac{b}{c}=\frac{b}{c/a}\]
In my problem I have to expand the problem ln(2x^6+3squareroot(x+8)/(x-1)^4
So just distributing to the numerator, assuming ita ln/1 would prbably be best, I think?
where is the closing bracket on the natural log?
It is supposed to be applied to the whole fraction.... sorry if it was confusing!
\[\ln\left(\frac{2x^6+3\sqrt{(x+8)}}{(x-1)^4}\right)\]?
Yes!
well the thing about logs ... \[\log ab=\log a+\log b\] \[\log \frac ab=\log a-\log b\]
So would I turn the numerator into ln((2x^6)(3sq.rt.x+8))?
where'd the plus go? \[\log a+b≠\log a+\log b=\log ab\]
Oh! I missunderstood. So now I have \[\ln \left( 2x ^{6} \right)+ \ln \left( 3\sqrt{x+8} \right)\]
In the numerator.
Thanks for all your help!
no you cant do that the whole numerator will stay in a single log, however you can simplify the log of the denominator
Join our real-time social learning platform and learn together with your friends!