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Show x^(log base x of y) = y
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let k=log base x of y then
x^k=y
so, k = log base x of y
thus, k = k (proved)
Ha ha ha..
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Let: \[\log_x(y) = m \implies x^m = y\] So: \[\large x^{\log_x(y)} \implies x^{\log_x(x^m)} \implies x^{m \cdot \log_x(x)} \implies x^m = y\]
\[\log_x(x) = 1\]
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