Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Show x^(log base x of y) = y

OpenStudy (anonymous):

let k=log base x of y then

OpenStudy (anonymous):

x^k=y

OpenStudy (anonymous):

so, k = log base x of y

OpenStudy (anonymous):

thus, k = k (proved)

OpenStudy (anonymous):

Ha ha ha..

OpenStudy (anonymous):

Let: \[\log_x(y) = m \implies x^m = y\] So: \[\large x^{\log_x(y)} \implies x^{\log_x(x^m)} \implies x^{m \cdot \log_x(x)} \implies x^m = y\]

OpenStudy (anonymous):

\[\log_x(x) = 1\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!