Question

Please help!
Find an equation in slope-intercept form for the line through points (-1, -4) and (3, 2)

Answer 1

Do you know the equation for Slope Intercept Form?

Answer 2

y=mx+b

Answer 3

Don't i need to put it in point slope first?

Answer 4

Good! So..Do you know how to find the slope of a line?

Answer 5

U don't have to. I can show u an easier way...if you want.

Answer 6

I know the slope formula, should i do that?

Answer 7

\[M = \frac{y2-y1}{x2-x1} \]
This is the gradient formula, and you can use this when there are two points and in this case there are two points provided of (-1,-4) and (3,2).

Answer 8

(-1,-4) and (3,2)
(x1,y1) (x2,y2)
now try using these values and substituting them into the gradient formula above.

Answer 9

So slope = 3/2

Answer 10

Does it matter which ordered pair i plug into y=mx+b?

Answer 11

Oh..ok i guess msamido can take it up for me:)

Answer 12

Well I have my slope, all i need now is the ordered pair to plug into the final equation right?

Answer 13

(-1, -4) and (3, 2)
U recall the equation for gradient
y2-y1=m(x2-x1)
(2+1)=m(3+4)
m=3/7
then take equation

y-y1=m(x-x1)
y-2=(7/3)(x-3)
y=((7x)/3)-5

Answer 14

But why did I go the slope formula and not get the same slope as you? Shouldn't both ways work?

Answer 15

post what U got @smagyar

Answer 16

\[(2+4) / (3+1) = 3/2\]

Answer 17

i had seen my mistake....i had exchanged da variabls sumwhr...but tried 2 correct it but it ddnt post ...i wll fix it

Answer 18

(-1, -4) and (3, 2)
U recall the equation for gradient
y2-y1=m(x2-x1)
(2+4)=m(3+1)
m=3/2
then take equation
y-y1=m(x-x1) y-2=(3/2)(x-3)
y=((3x)/2)-(5/2)

Answer 19

i hope is now clear

Answer 20

Thank you!!