Question

Given that tan(A+B)=45 deg. so find the value of (1+tanA)(1+tanB)....

Answer 1

2

Answer 2

Here I think your question is somewhat wrong:

\[\tan(A+B) = 1\]

It should be..

Answer 3

or A+B=45

Answer 4

Yes..

Answer 5

tan(A+B)=tan45 would be the right question

Answer 6

question is alright.....and the answer is 2 ...BUT HOW???? @abhiprabhu

Answer 7

The question is not right..

Answer 8

the correct question is tan(A+B)=tan45...for sure
and here's the solution
tan(A+B)=(tanA+tanB)/(1-tanA*tanB)=tan45=1
so,tanA+tanB=1-tanA*tanB
tanA+tanB+tanA*tanB=1
1+tanA+tanB+tanA*tanB=2
(1+tanA)(1+tanB)=2