Question

Derivation for the distance travelled in the nth second , Sn = u+( n-1/2)a .

Answer 1

what is u and a....... are they initial velocity and accleration

Answer 2

yeah !

Answer 3

so derivation of distance-time equation gives speed

Answer 4

what is the distance - time eqn ?

Answer 5

s=ut+1/2at^2 ?

Answer 6

suppose we have a equation x = 2t^2+3t , where x is the distance travelled by an onject at t seconds then the derivation of it will the speed of the object

Answer 7

okay !

Answer 8

must be mistake........

Answer 9

?

Answer 10

@sauravshakya what is the mistake ?

Answer 11

I am thinking........

Answer 12

hm..

Answer 13

Sorry....... will return in a few minutes

Answer 14

okay !

Answer 15

Can you wait a minute @ashna

Answer 16

For calculating distance traveled in nth second,

we find the distance traveled in \(n\) seconds and distance traveled in \((n-1)\) seconds and then subtract them:

So: here we are to find:

\[\large S_{nth} = S_n - S_{n-1}\]

Getting this much @ashna

Answer 17

@ashna are you there ??

Answer 18

I think this equation is for the distance travelled in the nth second..... Sn = u+( n-1/2)a

Answer 19

so what are u doing @waterineyes

Answer 20

I am deriving that equation.

Answer 21

oh......

Answer 22

Can I proceed ??

Answer 23

yep......

Answer 24

actually I got it

Answer 25

U should have used different notations..........

Answer 26

let us suppose Sn is the distance travelled by the object in the nth second and Tn be the distane travelled by the object in n second then,